(2x-3)(x^2+x-5)=

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Solution for (2x-3)(x^2+x-5)= equation: 


Simplifying
(2x + -3)(x2 + x + -5) = 0

Reorder the terms:
(-3 + 2x)(x2 + x + -5) = 0

Reorder the terms:
(-3 + 2x)(-5 + x + x2) = 0

Multiply (-3 + 2x) * (-5 + x + x2)
(-3(-5 + x + x2) + 2x * (-5 + x + x2)) = 0
((-5 * -3 + x * -3 + x2 * -3) + 2x * (-5 + x + x2)) = 0
((15 + -3x + -3x2) + 2x * (-5 + x + x2)) = 0
(15 + -3x + -3x2 + (-5 * 2x + x * 2x + x2 * 2x)) = 0
(15 + -3x + -3x2 + (-10x + 2x2 + 2x3)) = 0

Reorder the terms:
(15 + -3x + -10x + -3x2 + 2x2 + 2x3) = 0

Combine like terms: -3x + -10x = -13x
(15 + -13x + -3x2 + 2x2 + 2x3) = 0

Combine like terms: -3x2 + 2x2 = -1x2
(15 + -13x + -1x2 + 2x3) = 0

Solving
15 + -13x + -1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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